에러

def solution(table, languages, preference): answer = '' score = [] lan_idx = 0 max_score = [] qq = [] for i in table: score = [] for k in languages: if k in i.split(): score.append((6 - i.split().index(k))*preference[lan_idx % len(languages)]) else: score.append(0) lan_idx += 1 max_score.append(sum(score)) result = max(max_score) new_co = [i for i, ele in enumerate(max_score) if ele == result] p..

def solution(new_id): #1단계 new_id = new_id.lower() #2단계 new_word = '' for i in new_id: if i.isalnum() or i in '-_.': new_word += i new_id = new_word #3단계 while '..' in new_id: new_id = new_id.replace('..','.') #4단계 if(len(new_id)>0 and new_id[0]=='.'): new_id=new_id[1:] if(len(new_id)>0 and new_id[-1]=='.'): new_id = new_id[:-1] #5단계 if(len(new_id)==0): new_id = 'a' #6단계 if(len(new_id)>15): new_..

def solution(board, moves): answer = 0 basket = [] new_moves = [] for i in moves: new_moves.append(i-1) for k in new_moves: for i in range(len(board)): if board[i][k] == 0: continue basket.append(board[i][k]) if len(basket) > 1: if basket[-1] == basket[-2]: basket.pop() basket.pop() answer += 2 board[i][k] = 0 break return answer 리스트 삭제 부분 공부

def solution(s): answer = '' numbers = ["zero","one","two","three","four","five","six","seven","eight","nine"] for idx,num in enumerate(numbers): if num in s: //num 문자열이 s 문자열 안에 포함되어 있는지 s = s.replace(num,str(idx)) //포함되어 있다면 num 값 찾아서 숫자로 바꿔준다. answer = s return int(answer) 알게된 것- enumerate는 값과 인덱스 값을 같이 이용할 수 있다. s.replace("찾을값","고칠값",횟수) //고친s 반환 s.find("찾을값") // 찾을값이 없을경우 -1반환, 있을경우 찾는 값의 첫..

def solution(numbers, hand): answer = '' key_dic = { 1:(0,0), 2:(0,1), 3:(0,2), 4:(1,0),5:(1,1),6:(1,2), 7:(2,0),8:(2,1),9:(2,2), '*':(3,0),0:(3,1),'#':(3,2)} lastL = '*' lastR = '#' for n in numbers: if n in [1,4,7]: answer += 'L' lastL = n elif n in [3,6,9]: answer += 'R' lastR = n else: distL = abs(key_dic[n][0]-key_dic[lastL][0])+abs(key_dic[n][1]-key_dic[lastL][1]) distR = abs(key_dic[n][0]..